y^2+28y+60=0

Solution for y^2+28y+60=0 equation:

y^2+28y+60=0

a = 1; b = 28; c = +60;
Δ = b2-4ac
Δ = 282-4·1·60
Δ = 544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{544}=\sqrt{16*34}=\sqrt{16}*\sqrt{34}=4\sqrt{34}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-4\sqrt{34}}{2*1}=\frac{-28-4\sqrt{34}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+4\sqrt{34}}{2*1}=\frac{-28+4\sqrt{34}}{2}
$